[Tutor] problem solving with lists

[Dennis Lee Bieber]

On Fri, 18 Mar 2022 16:12:19 +0100, <marcus.luetolf at bluewin.ch> declaimed
the following:

>…many thanks for your quick replay.
>
>When I used a for loop :
>
> 
>
>>lst = [['a', 'b', 'c'], ['d', 'e', 'f'], ['a', 'b', 'g'], ['b', 'c', 'h']]
>
>>sub_lst = []
>
>>for p in lst:
>
>>    pair1 = lst[p][0:2]

	"p" IS the "sublist", not an index.

		pair1 = p[0:2]


-- 
	Wulfraed                 Dennis Lee Bieber         AF6VN
	wlfraed at ix.netcom.com    http://wlfraed.microdiversity.freeddns.org/