[Tutor] Basic Question

[Osmaan Mysorewala]

Thank you everyone for all your help. I feel a lot more better about global
variables now.

I thought that using several of statements looked somewhat messy and would
be hard to debug so that’s why I thought they might be bad.

To answer your question Mr Rafi, this isn’t for my homework, it’s a
personal project as I was trying to learn Python more.

On Fri, Sep 10, 2021 at 9:55 AM Mrb Rafi <mrbrafi1971 at gmail.com> wrote:

> Hello Osmaan,
>
> Are you working on this as a part of your homework?
> It's just yesterday when one of my friends asked me about this game. He has
> got this game as a homework in his varsity.
>
> Rafi
>
> On Fri, Sep 10, 2021 at 8:28 PM Peter Otten <__peter__ at web.de> wrote:
>
> > On 10/09/2021 10:21, Alan Gauld via Tutor wrote:
> > > On 09/09/2021 22:58, Osmaan Mysorewala via Tutor wrote:
> > >
> > >> One more question. In my get_neighbors function I use a terrible
> > >> if-statement spam, how would I go about replacing that?
> > > I assume you mean this section:
> > >
> > > def get_neighbors(a, b):
> > >      neighbors = 0
> > >      if old_arr[a + 1][b] == 1:
> > >          neighbors = neighbors + 1
> > >      if old_arr[a - 1][b] == 1:
> > >          neighbors = neighbors + 1
> >
> > > I don't think its terrible but it can be tidied up provided
> > > the values you store are zero and one. Then you can miss
> > > out the if statements and replace them with addition:
> > >
> > >      neighbors = neighbors + old_arr[a + 1][b] # or using +=...
> > >      neighbours += old_arr[a - 1][b]
> > >      neighbours += old_arr[a][b+1]
> >
> > Osmaan, while I agree with Alan that the if statements aren't "terrible"
> > I'd like to suggest that you revisit your failed attempt to use loops:
> >
> > >     for na in range(a - 1, a + 1):
> > >         for nb in range(b - 1, b + 1):
> > >             if (na != a and nb != b) and old_arr[na][nb]:
> > >                 neighbors = neighbors + 1
> >
> > This should work once
> >
> > (1) you get the range() calls right
> >
> > hint: Python's ranges are "half open", i. e. they do not include the
> > last value:
> >
> >  >>> list(range(3))
> > [0, 1, 2]
> >  >>> a = 42
> >  >>> list(range(a-1, a+1))
> > [41, 42]
> >
> > (2) in the first condition of the if statement you only exclude the cell
> > (a, b)
> >
> > hint: start with an expression that's true for (a, b), then negate that
> > with
> >
> > if not (...to be done...) and old_arr[na][nb]:
> >      ...
> >
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