[Tutor] modification to a list

[Subhash Nunna]

Hi Shubham,


Here is the code meeting you’re conditions:
def skip_elements(elements):
              # Initialize variables
              new_list = []
              i = 0

              # Iterate through the list
              for i,element in enumerate(elements):
                           # Does this element belong in the resulting list?
                           if elements.index(element)%2==0:
                                         # Add this element to the resulting list
                                         new_list.append(element)
                           # Increment i
                           i += 1


              return new_list

print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a', 'c', 'e', 'g']
print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach']
print(skip_elements([])) # Should be []

Regards,
Subhash Nunna

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From: shubham sinha<mailto:upwkwd at gmail.com>
Sent: Wednesday, April 22, 2020 8:17 PM
To: tutor at python.org<mailto:tutor at python.org>
Subject: [Tutor] modification to a list

Hi,
Q. The skip_elements function returns a list containing every other element
from an input list, starting with the first element. Complete this function
to do that, using the for loop to iterate through the input list.
my code:
def skip_elements(elements):
    new_list = [ ]
    i = 0
    for element in elements:
        if "element" != "elements(i):
            new_list.append(element)

        i += 2
    return new_list

print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a',
'c', 'e', 'g']
print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi',
'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach']
print(skip_elements([ ])) # Should be [ ]

my output:

['a', 'b', 'c', 'd', 'e', 'f', 'g']
['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach']
[]


output should be:

['a', 'c', 'e', 'g']

['Orange', 'Strawberry', 'Peach']

[]
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