[Tutor] creating dictionary from a list

[Saad Javed]

What just happened here? :)

I am trying to learn python so i'm sorry if my mistakes seem trivial.

On Saturday, April 13, 2013, Mark Lawrence wrote:

> On 13/04/2013 15:34, Saad Bin Javed wrote:
>
>> I ran into a bit of problem with my revised code based on Steven's
>> suggestions.
>>
>> lst = ['', 'Thu Apr 04           Weigh In', '', 'Sat Apr 06 Collect
>> NIC', '                     Finish PTI Video', '', 'Wed Apr 10  Serum
>> uric acid test', '', 'Sat Apr 13   1:00pm  Get flag from dhariwal', '',
>> 'Sun Apr 14      Louis CK Oh My God', '', '']
>>
>> lst = filter(None, lst)
>> lst = [item.split('  ') for item in lst]
>> lst = [item for sublist in lst for item in sublist]
>> lst = filter(None, lst)
>>
>> This code would produce:
>>
>> ['Thu Apr 04', ' Weigh In', 'Sat Apr 06', ' Collect NIC', ' Finish PTI
>> Video', 'Wed Apr 10', ' Serum uric acid test', 'Sat Apr 13', ' 1:00pm',
>> 'Get flag from dhariwal', 'Sun Apr 14', ' Download Louis CK Oh My God']
>>
>> dict = {}
>> for item in lst:
>>      if item.startswith(('Mon','Tue','**Wed','Thu','Fri','Sat','Sun'))**:
>>
>>          dict.update({lst[lst.index(**item)].lstrip():
>> lst[lst.index(item)+1].lstrip(**)})
>> print dict
>>
>> Such a dictionary would only add the item next to the date as the value.
>> But from the list you can see 'Sat Apr 06' has two items on the agenda
>> while 'Sat Apr 13' show item and a time. So you can understand why such
>> a dict would be useless.
>>
>> I want all agenda items joined as a comma delimited string and added to
>> the date key as a value. I've been mulling over how to go about it. One
>> idea was to get indices of dates in the list and add all items in
>> between them as values.
>>
>> index_keys = [] #0, 2, 5, 7, 9
>> index_values = [] #1, 3, 4, 6, 8, 10
>> for item in lst:
>>      if
>> item.lstrip().startswith(('**Mon','Tue','Wed','Thu','Fri','**
>> Sat','Sun')):
>>          index_keys.append(lst.index(**item))
>>      else:
>>          index_values.append(lst.index(**item))
>>
>> But I can't quite get it to understand that i want all items between
>> position 0 and 2 in the list to be assigned to item at 0 in the
>> dictionary and so forth.
>>
>> Ideas?
>>
>>
> Don't fight Python, unlike this chap[1] :)  Basically if you're looping
> around any data structure you rarely need to use indexing, so try this
> approach.
>
> for item in lst:
>     if item.startswith(('Mon','Tue','**Wed','Thu','Fri','Sat','Sun'))**:
>         myDict[item] = []
>         saveItem = item
>     else:
>         myDict[saveItem].append(item.**strip())
>
>
> [1]http://www.bbc.co.uk/news/**world-us-canada-22118773<http://www.bbc.co.uk/news/world-us-canada-22118773>
>
> --
> If you're using GoogleCrap™ please read this http://wiki.python.org/moin/*
> *GoogleGroupsPython <http://wiki.python.org/moin/GoogleGroupsPython>.
>
> Mark Lawrence
>
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