[Tutor] string to binary and back... Python 3

[Prasad, Ramit]

> > bin(integer).split('b')[1].zfill( multiple_of_eight )
> OK so using this: Hopefully my copy paste works this time.
> 
> bin_data = ''
> 
> for char in data:
> 
> bin_data += bin(ord(char)).split('b')[1].zfill(8)
> 
> print(bin_data)
> 
> bin_list = [bin_data[x:x + 2] for x in range(0, len(bin_data), 2)]
> 
> print(bin_list)
> 
> 
> 
> The paste looks good to me at this time.

Not to me, but I can probably figure out enough based on this.

> How do I get back to the string? If I use this:
> 
> data2 = []
> 
> for item in bin_list:
> 
> data2.append(int(item, 2))
> 
> print(data2)
> 
> 
> 
> The output is all too low of numbers for ord() to convert back to the
> correct string.
> >

Sure, this makes perfect sense to me :) (adding indent)

for char in data:
    bin_data += bin(ord(char)).split('b')[1].zfill(8)
bin_list = [bin_data[x:x + 2] for x in range(0, len(bin_data), 2)]

Why are you grabbing 2 binary digits? The only possibilities are 0,1,2,3
and none are ASCII letters. You should be grabbing 8 at a time.

bin_data = [ bin(ord(char)).split('b')[1].zfill(8) for char in data ]
bin_string = ''.join(bin_data)
bin_list = [ chr( int(char, 2) ) for char in bin_data ]

I am not really sure what you are getting at with XOR and one time
padding, but it has been a while since I have done any encryption.

I would think you could do all this by just converting everything
to int and then adding/replacing the pad in the list of ints.


Ramit

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