[Tutor] Sum files' size

[Susana Iraiis Delgado Rodriguez]

Thank you to all of you!

After I read your mails I started to modify my code, I applied Ramit
suggestion and got the result I wanted:

mport os
file_list = []
folders = None
for root, folders, files in os.walk('C:\\'):
            file_list.extend(os.path.join(
root,fi) for fi in files if (fi.endswith.shp))
for row, filepath in enumerate(file_list, start=1):
            n = os.path.splitext(filepath)
            p = n[0]+'.prj'
            shx = n[0]+'.shx'


#Function to get size in humam readable terms:
            def sizeof_fmt(num):
                 for x in ['bytes','KB','MB','GB','TB']:
                      if num < 1024.0:
                           return "%3.1f%s" % (num, x)
                      num /= 1024.0
            s = os.path.getsize(filepath)
            shx1 = os.path.getsize(shx)
            p1 = s = os.path.getsize(p)
total = sizeof_fmt(s+shx1+p1)



2011/7/28 Prasad, Ramit <ramit.prasad at jpmchase.com>

> >kb = sizeof_fmt(s)
> >shx1 = os.path.getsize(shx)
> >kb2 = sizeof_fmt(shx1)
> > total = kb+kb2+kb3
>
> Instead only retrieve the formatted output at the end. That way you will
> not have to worry about converting back from strings, nor have to worry
> about adding number with different units (e.g. 10KB + 10MB).
>
> kb = s
> kb2 = os.path.getsize(shx)
> total = sizeof_fmt(kb+kb2+kb3)
>
> Ramit
>
>
> Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology
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