[Tutor] Rounding a Python float to the nearest half integer

[Wayne Werner]

On Fri, Oct 8, 2010 at 7:51 AM, Sithembewena Lloyd Dube
<zebra05 at gmail.com>wrote:

> Hi folks,
>
> Supposing I had the float 4.4348 and I wished to round it off to the
> nearest half-integer upwards or downwards, how would I go about it?
>

You can use round:

round(4.4348) -> 4.0

But if you want to specify the behavior you can do something like this:

x = 4.4348
if x % 1 >= 0.5:
   x = x/1+1
else:
   x = x/1

HTH,
Wayne
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