[Tutor] Text matching

[Gardner, Dean]

Here is a test sample of what I have: This currently correctly
identifies the start and the end of the changelog entries and I can
identify the requested item records. What I am struggling with at
present is to how to create records of the full changelog entries for
each of the found items.

Again any help greatly appreciated.


uid = "000028.txt"


file = open("C:\projects\SuiteSpecification\Notes\ChangeLog.txt")

output = file.readlines()
changeLogList = []
itemList = []
for strOut in output:

    if "----" in strOut:
        changeLogStart = 1
    itemList.append(strOut)       
    if "Reviewed:" in strOut:
        changeLogStart=0
for item in itemList:
    if uid in item:
        print item


Dean Gardner
Test Engineer 
Barco
Bonnington Bond, 2 Anderson Place, Edinburgh EH6 5NP, UK
Tel + 44 (0) 131 472 5731 Fax + 44 (0) 131 472 4799
www.barco.com 
dean.gardner at barco.com 


-----Original Message-----
From: Kent Johnson [mailto:kent37 at tds.net] 
Sent: 03 May 2007 13:46
To: Gardner, Dean
Cc: tutor at python.org
Subject: Re: [Tutor] Text matching

Gardner, Dean wrote:
> Hi Folks
> 
> I wish to isolate certain changelog entries and display them to the 
> user, for example:
> 
> Changelog.txt
> 
> ----------Some Module <Tag> ---------- M 000751 - Title
>>  what was amended
> Reviewed by: Someone
> 
> For this text file I wish to find all entries for 000751 and then 
> present each of the changelog entries.
> 
> My thought was to
> identify the "----" with a regular expression identifying this as the 
> changelog start

You probably don't need a regex here, something like
   if line.startswith('----------'):
will probably work

> attempt to find the item number

   if line.split()[1] == '000751':

> if it isn't found move on, if it is found then add this to a list.
> 
> But I feel as though there must be a simpler and more effecient way.

This sounds good to me except for the regex. Can you show us your code?

Kent



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