[Tutor] Zipfile and File manipulation questions.

[Chris Hengge]

Guess nobody has had a chance to point me in the write direction on this
problem yet?

Thats ok, I've gotten a ton of other code written, and I'll come back to
this tricky part later.

This particular project I've been working on to automate some of my job at
work has been an excellent learning experience. :D

On 10/14/06, Chris Hengge <pyro9219 at gmail.com> wrote:
>
> I was using afile.split("/"), but I'm not sure how to impliment it...
>
> if "/" in afile: (for some reason I can't add 'or "\" in afile' on this
> line)
>                 outfile = open(afile, 'w') # Open output buffer for
> writing. (to open the file, I can't split here)
>                 outfile.write(zfile.read(afile)) # Write the file. (
> zfile.read(afile)) wont work if I split here...)
>                 outfile.close() # Close the output file buffer.
>
> On 10/14/06, Kent Johnson <kent37 at tds.net> wrote:
> >
> > Chris Hengge wrote:
> > > Ok, last problem with this whole shebang...
> > >
> > > When I write the file from the zip, if it is in a subfolder, it will
> > > error..
> > > The code below will detect if the file in contained inside a directory
> >
> > > in the zip, but I just want it to write it like it wasn't.
> > > Another words
> > >
> > > Zipfile.zip looks like this
> > > file.ext
> > > file2.ext
> > > folder/
> > >         anotherfile.ext
> > >
> > > file.ext extracts fine, file2.ext extracts file.. but it see's the
> > last
> > > file as folder/anotherfile.ext and it can't write it.. I tried to
> > figure
> > > out how to use .split to get it working right.. but I'm not having any
> >
> > > luck.. Thanks.
> > >
> > > for afile in zfile.namelist(): # For every file in the zip.
> > >         # If the file ends with a needed extension, extract it.
> > >         if afile.lower().endswith('.cap') \
> > >         or afile.lower().endswith('.hex') \
> > >         or afile.lower().endswith('.fru') \
> > >         or afile.lower().endswith('.cfg'):
> > >             if afile.__contains__("/"):
> >
> > This should be spelled
> >    if "/" in afile:
> >
> > __contains__() is the method used by the python runtime to implement
> > 'in', generally you don't call double-underscore methods yourself.
> >
> > I think you want
> >    afile = afile.rsplit('/', 1)[-1]
> >
> > that splits afile on the rightmost '/', if any, and keeps the rightmost
> > piece. You don't need the test for '/' in afile, the split will work
> > correctly whether the '/' is present or not.
> >
> > If you are on Windows you should be prepared for paths containing \ as
> > well as /. You can use re.split() to split on either one.
> >
> > Kent
> > >                 outfile = open(afile, 'w') # Open output buffer for
> > > writing.
> > >                 outfile.write(zfile.read(afile)) # Write the file.
> > >                 outfile.close() # Close the output file buffer.
> > >             else:
> > >                 outfile = open(afile, 'w') # Open output buffer for
> > > writing.
> > >                 outfile.write(zfile.read(afile)) # Write the file.
> > >                 outfile.close() # Close the output file buffer.
> >
> >
> >
>
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