[Tutor] making list into a dictionary

[McLaughlin, Toby]

Even

c = dict(zip(a,b))

will work because of the overloaded constructor on "dict".

>From help(dict)
	class dict(object)
	 |  dict() -> new empty dictionary.
	<snip>
	 |  dict(seq) -> new dictionary initialized as if via:
	 |      d = {}
	 |      for k, v in seq:
	 |          d[k] = v

Toby McLaughlin.

> -----Original Message-----
> From: tutor-bounces at python.org 
> [mailto:tutor-bounces at python.org] On Behalf Of Bill Mill
> Sent: Friday, 5 November 2004 3:44 PM
> To: kumar s
> Cc: tutor at python.org
> Subject: Re: [Tutor] making list into a dictionary
> 
> 
> Kumar,
> 
> Here's what I'd do:
> 
> a = [1,2,3]
> b = ['a','b','c']
> d = {}
> 
> for key, val in zip(a, b):
>     d[key] = val
> 
> The trick here is in the zip() function. This combines two lists like
> a zipper - first element of the first list followed by first element
> of the second list, then the second element of the first, and so on.
> An example might help more:
> 
> >>> a = [1,2,3]
> >>> b = ['a', 'b', 'c']
> >>> zip(a,b)
> [(1, 'a'), (2, 'b'), (3, 'c')]
> 
> The resulting list of tuples is easy to unpack, as we showed in the
> earlier example.
> 
> Peace
> Bill Mill
> bill.mill at gmail.com
> 
> 
> On Thu, 4 Nov 2004 20:18:45 -0800 (PST), kumar s 
> <ps_python at yahoo.com> wrote:
> > Dear group,
> >  I want to convert 2 lists into a dictionary object.
> > 
> > Can I do that using list comprehension or by any other
> > method:
> > 
> > a = ['apple', 'carrot', 'egg', 'cicken']
> > b = ['fruit', 'vegie', 'poultry', 'meat']
> > 
> > c = {}
> > 
> > I want to create:
> > c = {'fruit':'apple',
> > 'vegie':'carrot',
> > 'poultry':'egg',
> > 'mean':'chicken'}
> > 
> > Could any one help, please.
> > 
> > Thanks
> > Kumar.
> > 
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