[Tutor] Re: a list comp

[aon.912502367 at aon.at]

----- Original von:  RoT <RoT at 245t.com>:

> Basically you can observe this here:
> 
>  >>> newlist = []
>  >>> print newlist.append(3)
> None
>  >>> newlist
> [3]
>  >>> print newlist.append(5)
> None
>  >>> newlist
> [3, 5]
>  >>> newlist = []
>  >>> print [newlist.append(x) for x in 1,3,5]
> [None, None, None]
 even though
newlist.append(x) returns None, the list comp 'does' evaluate to a new list doesn,t it

>  >>> [index for index in del_list if index not in keep_list]
> [2, 4, 8]

so I still would have expected it to be returned. 

It's shown in the above example: the list comprehension
returned [None, None, None] because each call of the
append-method returns None-
Gregor

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