[Tutor] Using re/search with dictionaries

[Jackson]

Kirby --
Thanks for your reply. It fit the bill perfectly for what I need.

David




---------- Original Message ----------------------------------
From: Kirby Urner <urnerk@qwest.net>
Date: Wed, 31 Oct 2001 09:24:56 -0800

>
>Regular expressions search strings, not lists, so you
>can't use d.keys() as an arg to re.search() -- would have
>to do some conversion to/from to make this approach work.
>
>But regular expressions might be overkill if you're just
>wanting to find keys with embedded strings, nothing much
>fancier.  Simpler string functions will do that job.
>
>Defining dictionary d as per your setup script, the
>function below lists all key/value pairs where the
>passed pattern (e.g. "blue") is found in the key:
>
>   >>> def getmatches(pattern, thedict):
>            keys = [i for i in thedict.keys() if i.find(pattern)>=0]
>            for k in keys:
>               print "%s = %s" % (k,thedict[k])
>
>
>   >>> getmatches("blue",d)
>   blue-003 = ['blueberry muffins']
>   blue-002 = ['blueberry cobbler']
>   blue-001 = ['blueberry pie']
>   blueberry = ['muffins']
>   bluebird = ['feathered friend']
>
>You could modify the above to work with regular expressions,
>but it'd search each key, one at a time.  Again, if simple
>string functions will do the job, they're faster.
>
>Kirby
>
>At 10:04 AM 10/31/2001 -0700, Jackson wrote:
>>Greetings --
>>How do I search dict keys? and return the records that go along with them? 
>>It seems as if it should be something along this line:
>>
>># we're looking for keys/records with blue* in them.
>>m=rd.search("\w[blue]+",d.keys())
>>if m: print repr(m.group(0))
>>    and the output should be:
>>
>>[blue-001"]=["blueberry pie"]
>>["blue-002"]=["blueberry cobbler"]
>>["blue-003"]=["blueberry muffins"]
>>...
>>....
>>
>>
>>Thanks for you time
>>David Jackson
>
>
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