[Tkinter-discuss] Stopping a for loop with a sleep() funciton in it

[Guilherme Polo]

On Thu, Jul 10, 2008 at 8:24 PM, Alexnb <alexnbryan at gmail.com> wrote:
>
>
>
> Guilherme Polo wrote:
>>
>> On Thu, Jul 10, 2008 at 7:31 PM, Alexnb <alexnbryan at gmail.com> wrote:
>>>
>>>
>>>
>>> Guilherme Polo wrote:
>>>>
>>>> On Thu, Jul 10, 2008 at 5:57 PM, Alexnb <alexnbryan at gmail.com> wrote:
>>>>>
>>>>> Okay, so I have a for loop with a sleep command. I want the loop to
>>>>> continue
>>>>> until it is told to stop. I want to tell it to stop when a list goes
>>>>> from
>>>>> empty to having something. The problem is that when that loop starts,
>>>>> the
>>>>> program pretty much stops with it.
>>>>
>>>> You need to remove the use of sleep and use "after" instead. You keep
>>>> scheduling your task till the condition is not met anymore, then you
>>>> stop scheduling it with "after".
>>>>
>>>>> To make things harder, I really want that
>>>>> to be it's own class, so I have to pass it the list that triggers the
>>>>> stopping, but I can only pass it the list once. So I don't think it is
>>>>> possible.
>>>>
>>>> It is, just pass some other object along which can call the method
>>>> "after".
>>>>
>>>>> But if this made sense to anyone, and you have a suggestion I
>>>>> would love it. Heres the full code: (but at the bottom, the Open
>>>>> function
>>>>> is
>>>>> really the only thing that matters)
>>>>>
>>>>
>>>> If you want help based on code, you have to post a short-enough code
>>>> that demonstrates the problem.
>>>>
>>>>> from Tkinter import *
>>>>> import time
>>>>>
>>>>> class BusyBar(Frame):
>>>>> ...
>>>>
>>>>
>>>>
>>>> --
>>>> -- Guilherme H. Polo Goncalves
>>>> _______________________________________________
>>>> Tkinter-discuss mailing list
>>>> Tkinter-discuss at python.org
>>>> http://mail.python.org/mailman/listinfo/tkinter-discuss
>>>>
>>>>
>>>
>>> Okay, so I modified the bottom code to this:
>>>
>>> def Open(root):
>>>
>>>    bb = BusyBar(root, text='Grabbing Definitions')
>>>    bb.pack(side=LEFT, expand=NO)
>>>
>>>
>>>    def sleeper():
>>>        root.update
>>
>> What if you change this to root.update() ?
>>
>>>        root.after(1, sleeper)
>>
>> after works with milliseconds, not seconds, be aware.
>>
>>>    bb.on()
>>>    root.update_idletasks()
>>>
>>>    sleeper()
>>>
>>>    #for i in range(0, 100):
>>>        #time.sleep(0.1)
>>>        #root.update()
>>>    bb.of()
>>>
>>> but it doesn't repeat. What am I missing?
>>>
>>
>>
>> --
>> -- Guilherme H. Polo Goncalves
>> _______________________________________________
>> Tkinter-discuss mailing list
>> Tkinter-discuss at python.org
>> http://mail.python.org/mailman/listinfo/tkinter-discuss
>>
>>
>
> Well, what was happening before is that the bar would just be at a
> standstill. After making it update() it moved a little, but was just a
> standstill at a different place, if that makes sense. Any more ideas? heres
> the code:
>
> def Open(root):
>
>    bb = BusyBar(root, text='Grabbing Definitions')
>    bb.pack(side=LEFT, expand=NO)
>
>    bb.on()
>    root.update_idletasks()
>
>    def sleeper():
>        root.update()
>        root.after(1, sleeper)

Did you ignore my last email where I said after takes milliseconds,
not seconds ? And this will forever, not what you want apparently.

>
>    sleeper()
>
>    #for i in range(0, 100):
>        #time.sleep(0.1)
>        #root.update()
>    bb.of()

The code you have pasted in the last two emails don't show the problem
you are having. I guess someone else will have to look at your entire
code to give more help.

>
> --
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> Sent from the Python - tkinter-discuss mailing list archive at Nabble.com.
>
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>



-- 
-- Guilherme H. Polo Goncalves