[SciPy-User] butter() and filtfilt() - differences between MATLAB and scipy

Paul Blelloch paul.blelloch at ata-e.com
Fri Jun 28 11:45:54 EDT 2013


I ran the same butterworth filter problem and got the following results:

>>> w=2./(256./2.)
>>> b,a=butter(9,w)
>>> b
array([  2.52984969e-14,   1.01193988e-13,   2.36119304e-13,
         3.54178956e-13,   3.54178956e-13,   2.36119304e-13,
         1.01193988e-13,   2.52984969e-14,   2.81094410e-15])
>>> a
array([   1.        ,   -8.71731939,   33.77839104,  -76.36014168,
        110.98476353, -107.55300968,   69.49343715,  -28.86903222,
          6.99664203,   -0.75373077])

These numerator values are different from Matlab's, which are:

b =
  Columns 1 through 6
   2.7931e-15   2.5138e-14   1.0055e-13   2.3462e-13   3.5193e-13   3.5193e-13
  Columns 7 through 10
   2.3462e-13   1.0055e-13   2.5138e-14   2.7931e-15
a =
  Columns 1 through 6
   1.0000e+00  -8.7173e+00   3.3778e+01  -7.6360e+01   1.1098e+02  -1.0755e+02
  Columns 7 through 10
   6.9493e+01  -2.8869e+01   6.9966e+00  -7.5373e-01

I don't know why my numerator values are so different from yours.  I'm using a 64-bit MKL optimized version of scipy 0.12.0.  The differences between Matlab and scipy are on very small numbers.  If you use a lower order filter, where the denominator coefficients are significant there are no differences between Matlab and scipy.  The Matlab results may well be more accurate based on a difference in order of operations or something, but when I compared the 'filtfilt' output from the two sets of coefficients applied to white noise I didn't see much difference.  What was more interesting to me was that the filtfilt results from Matlab were quite different in the initial transient than the filtfilt results from scipy using the same coefficients.  It does appear to me that there's a difference in the application of the filtfilt function.

-Paul

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Today's Topics:

   1. SciPy ecosystem and Python 3 (Thomas Kluyver)
   2. Re: noob question: numpy copy vs standard lib copy (Joon Ro)
   3. butter() and filtfilt() - differences between MATLAB	and
      scipy (Tristan Strange)
   4. Re: butter() and filtfilt() - differences between MATLAB and
      scipy (Fabrice Silva)
   5. Re: butter() and filtfilt() - differences between MATLAB	and
      scipy (Roger Fearick)
   6. Re: butter() and filtfilt() - differences between MATLAB and
      scipy (Tristan Strange)


----------------------------------------------------------------------

Message: 1
Date: Fri, 28 Jun 2013 01:22:37 +0100
From: Thomas Kluyver <takowl at gmail.com>
Subject: [SciPy-User] SciPy ecosystem and Python 3
To: SciPy Users List <scipy-user at scipy.org>
Message-ID:
	<CAOvn4qgHQU1pRmUkR26rrhhq-kenJc4Q=bgukyDboMLsmk=aMw at mail.gmail.com>
Content-Type: text/plain; charset="iso-8859-1"

At a conversation over lunch here at the SciPy conference, a few of us mentioned that we're starting to use Python 3 in earnest for our work.

For new users, the choice of two major Python versions is confusing and offputting, and we're not going to completely get rid of that confusion until we can simply point new users to Python 3. Most of our introductions, like the SciPy stack install page, point to Python 2 because of the ecosystem, but more and more packages now support Python 3, and we're reaching the point where we could reasonably recommend Python 3 for new users.

The aim of this post is to get an overview of where the ecosystem is with:
- What packages don't yet support Python 3, or are still too unstable?
- How important are each of those: how widely relevant are they, and are substitutes available?
- What other conditions need to be met to recommend Python 3? E.g.
Scientific Python distros, Linux distro packaging, documentation, etc.

Thanks,
Thomas
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Message: 2
Date: Thu, 27 Jun 2013 23:19:00 -0500
From: Joon Ro <joonhyoung.ro at gmail.com>
Subject: Re: [SciPy-User] noob question: numpy copy vs standard lib
	copy
To: SciPy Users List <scipy-user at scipy.org>
Message-ID:
	<CABeq5B_b5DBYL3=cM3DabxeD7HEB53G8WMpWYpt6_483f9pPEg at mail.gmail.com>
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On Mon, May 13, 2013 at 3:23 PM, psoriasis <adiamondcsi at gmail.com> wrote:

I'm new to python.  As I understand it, assignment copies by reference
> and to do otherwise requires a function like the standard library's 
> copy or deepcopy functions.  However, from what I see numpy has it's 
> own copy function and using it on a random object (instance of a test 
> class I made up not an array etc) doesn't seem to return the expected
> copy object.    I did try importing the copy module and that worked
> but then the numpy copy module was "shadowed" but I don't know if 
> that's a problem.
>
> Still, I'm sure numpy users need to copy regular objects so what's the 
> standard solution to this?
>
> Hi,

If you import those modules like import copy and import numpy as np, then you would use those functions with copy.copy() and np.copy() so you would not have the issue.

If you import those modules by from copy import * and from numpy import *, and you would have the problem. The first importing method is recommended one since by looking at your code it is explicit where the function comes from.

But, if you use numpy functions a lot (especially if you are interactively exploring), then I would import numpy with from numpy import * and import copy module with import copy (or import copy as cp) and make copy.copy()explicit.

Let me know if this is not clear.

Best,
Joon
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Message: 3
Date: Fri, 28 Jun 2013 11:08:32 +0100
From: Tristan Strange <tristan.strange at gmail.com>
Subject: [SciPy-User] butter() and filtfilt() - differences between
	MATLAB	and scipy
To: scipy-user at scipy.org
Message-ID:
	<CABQkF0mZ4_XBKVQQPK47d-uEVSMB_kQHH4LKhkPWQEYxxEcJbw at mail.gmail.com>
Content-Type: text/plain; charset="iso-8859-1"

Hi all,

I'm porting a script form MATLAB to Python and am getting very different results form the butter functions in the languages.

In MATLAB when I do the following:

w=2/(256/2);
[b,a]=butter(9,w,'low');

b comes out as a matrix containing :

2.8109e-15   2.5298e-14   1.0119e-13   2.3612e-13   3.5418e-13   3.5418e-13
2.3612e-13   1.0119e-13   2.5298e-14   2.8109e-15

When done in Python using scipy.signal's butter like so:

w = 2.0 / (256.0 / 2.0)
b, a = butter(9, w, 'low')

I get the following array with only a single value for b:

array([  2.81094410e-15])

and the following warning is issued:

/usr/lib/python2.7/dist-packages/scipy/signal/filter_design.py:288:
BadCoefficients: Badly conditioned filter coefficients (numerator): the results may be meaningless  "results may be meaningless", BadCoefficients)

Both functions in MATLAB and Python output the same a.

When using these values in filtfilt() I get totally different results. I've tried exporting b from MATLAB and loading it in to Python and passing that in to filtfilt() but still get totally diffreent results.

Can anyone tell me how to port this MATLAB code to Python such that the results are the same or explain what the problem is?

Many thanks,
Tristan
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Message: 4
Date: Fri, 28 Jun 2013 13:18:12 +0200
From: Fabrice Silva <silva at lma.cnrs-mrs.fr>
Subject: Re: [SciPy-User] butter() and filtfilt() - differences
	between MATLAB and scipy
To: scipy-user at scipy.org
Message-ID: <1372418292.5177.16.camel at laptop-101>
Content-Type: text/plain; charset="UTF-8"

Tristan Strange a ?crit :
> In MATLAB [...] b comes out as a matrix containing :
> 
> 2.8109e-15   2.5298e-14   1.0119e-13   2.3612e-13   3.5418e-13   3.5418e-13
> 2.3612e-13   1.0119e-13   2.5298e-14   2.8109e-15
> 
> When done in Python using scipy.signal's butter like so:
> [...] the following warning is issued:
> 
> /usr/lib/python2.7/dist-packages/scipy/signal/filter_design.py:288:
> BadCoefficients: Badly conditioned filter coefficients (numerator): 
> the results may be meaningless  "results may be meaningless", 
> BadCoefficients)

You should maybe worry about getting (in matlab) such values for b. All are pretty close to 0. This is what scipy implementation is warning you about ("Badly conditioned filter coefficients (numerator): the results may be meaningless"). Using this b vector may lead to output signals prone to numerical noise...




------------------------------

Message: 5
Date: Fri, 28 Jun 2013 11:23:42 +0000
From: Roger Fearick <roger.fearick at uct.ac.za>
Subject: Re: [SciPy-User] butter() and filtfilt() - differences
	between MATLAB	and scipy
To: SciPy Users List <scipy-user at scipy.org>
Message-ID:
	<DD0049064BE06D49B33A7908C703601825547269 at srvwinexc002.wf.uct.ac.za>
Content-Type: text/plain; charset="windows-1252"

You're using Python 2.7: maybe 2/(256/2) = 0.
________________________________

Hi all,

I'm porting a script form MATLAB to Python and am getting very different results form the butter functions in the languages.

In MATLAB when I do the following:

w=2/(256/2);
[b,a]=butter(9,w,'low');

b comes out as a matrix containing :

2.8109e-15   2.5298e-14   1.0119e-13   2.3612e-13   3.5418e-13   3.5418e-13 2.3612e-13   1.0119e-13   2.5298e-14   2.8109e-15

When done in Python using scipy.signal's butter like so:

w = 2.0 / (256.0 / 2.0)
b, a = butter(9, w, 'low')

I get the following array with only a single value for b:

array([  2.81094410e-15])

and the following warning is issued:

/usr/lib/python2.7/dist-packages/scipy/signal/filter_design.py:288: BadCoefficients: Badly conditioned filter coefficients (numerator): the results may be meaningless  "results may be meaningless", BadCoefficients)

Both functions in MATLAB and Python output the same a.

When using these values in filtfilt() I get totally different results. I've tried exporting b from MATLAB and loading it in to Python and passing that in to filtfilt() but still get totally diffreent results.

Can anyone tell me how to port this MATLAB code to Python such that the results are the same or explain what the problem is?

Many thanks,
Tristan

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Message: 6
Date: Fri, 28 Jun 2013 12:46:54 +0100
From: Tristan Strange <tristan.strange at gmail.com>
Subject: Re: [SciPy-User] butter() and filtfilt() - differences
	between MATLAB and scipy
To: SciPy Users List <scipy-user at scipy.org>
Message-ID:
	<CABQkF0mcPmD-4dOpR93X-uqBq3D_JkVDhO19Mcv-ay+UpJdmkw at mail.gmail.com>
Content-Type: text/plain; charset="iso-8859-1"

On 28 June 2013 12:23, Roger Fearick <roger.fearick at uct.ac.za> wrote:

>  You're using Python 2.7: maybe 2/(256/2) = 0.
>

It's not this I'm afraid. I import division from __future__

>Tristan Strange a ?crit :
>> In MATLAB [...] b comes out as a matrix containing :
>>
>> 2.8109e-15   2.5298e-14   1.0119e-13   2.3612e-13   3.5418e-13
3.5418e-13
>> 2.3612e-13   1.0119e-13   2.5298e-14   2.8109e-15
>>
>> When done in Python using scipy.signal's butter like so:
>> [...] the following warning is issued:
>>
>> /usr/lib/python2.7/dist-packages/scipy/signal/filter_design.py:288:
>> BadCoefficients: Badly conditioned filter coefficients (numerator): 
>> the results may be meaningless  "results may be meaningless",
BadCoefficients)

> You should maybe worry about getting (in matlab) such values for b. 
> All are pretty close to 0. This is what scipy implementation is 
> warning you about ("Badly conditioned filter coefficients (numerator): 
> the results may be meaningless"). Using this b vector may lead to 
> output signals prone to numerical noise...

Ok, thanks. Apparently the MATLAB implementation functions as expected....

Any one else have any ideas?

Cheers,
Tristan
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