[SciPy-User] masking an array ends up flattening it

[Oleksandr Huziy]

Hi,
I don't think it is possible, and also not sure if the order will be conserved
when you select and reshape.

Why do you need it? Think what would you like to get in the case when
you have only one element True?

Cheers
--
Oleksandr Huziy

2012/2/28 Johann Cohen-Tanugi <johann.cohentanugi at gmail.com>:
> Hello,
> I have the following:
> In [145]: m
> Out[145]:
> array([[  1.82243247e-23,  -5.53103453e-14,   4.32071039e-13,
>           0.00000000e+00],
>        [ -5.52425949e-14,   6.26697129e-02,  -5.12076585e-02,
>           0.00000000e+00],
>        [  4.31598429e-13,  -5.12102340e-02,   6.27539118e-02,
>           0.00000000e+00],
>        [  0.00000000e+00,   0.00000000e+00,   0.00000000e+00,
>           1.00000000e+10]])
>
> In [146]: mask
> Out[146]:
> array([[ True,  True,  True, False],
>        [ True,  True,  True, False],
>        [ True,  True,  True, False],
>        [False, False, False, False]], dtype=bool)
>
> Naively, I thought I would end up with a (3,3) shaped array when
> applying the mask to m, but instead I get :
>
> In [147]: m[mask]
> Out[147]:
> array([  1.82243247e-23,  -5.53103453e-14,   4.32071039e-13,
>         -5.52425949e-14,   6.26697129e-02,  -5.12076585e-02,
>          4.31598429e-13,  -5.12102340e-02,   6.27539118e-02])
>
> In [148]: m[mask].shape
> Out[148]: (9,)
>
> Is there another way to proceed and get directly the (3,3) shaped masked
> array, or do I need to reshape it by hand?
>
> thanks a lot in advance,
> Johann
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