Here's what I wrote for finding extrema of a 1D array
def extrema(signal, hilow="Hi"):
''' hilow = "Hi", "Low", or "Both" depending on whether you want
upper or lower extrema, or all of them.
'''
a = np.sign(np.diff(signal))
zerolocs = np.transpose(np.where( (a[1:]+a[0:-1]==0.) + (a==0.)[0:-1] )).flatten() + 1
zerolocs = zerolocs[zerolocs>=a.argmax()] # remove leading zeros
if zerolocs[0] < 1:
zerolocs = zerolocs[1:]
if zerolocs[-1]>len(a)-1:
zerolocs = zerolocs[0:-1]
if hilow == "Low" :
return zerolocs[np.where(a[zerolocs] >0)]
elif hilow == "Hi" :
return zerolocs[np.where(a[zerolocs] <=0)]
else :
return zerolocs
>Hi,
>
>You could create multiple thresholds along one axis of the array, and
>get all elements above each threshold value (=region). You build a
>region-stack from this; a 2D/3D boolean array that says which elements
>are above the threshold value for each threshold you used. If a region
>contains a region in a higher threshold value level (higher up in the
>stack) that means you haven't found the local maximum yet; if it
>doesn't, that is your top.
>
>This method would allow flats to be detected as well.
>
>The last thing you have to do is: for every remaining region that is a
>local maximum, you compute the coordinates and value as the mean of
>all coordinates or values contained in the region.
>
>Hope this helps
>Martin
>
>
>2009/8/26 fred <fredmfp at gmail.com>:
>> Hi,
>>
>> I would like to compute local extrema of an array (2D/3D),
>> ie get a list of points (coords + value).
>>
>> How could I do this?
>>
>> Any hint?
>>
>> TIA.
>>
>> Cheers,
>>
>> --
>> Fred
>> _______________________________________________
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>> SciPy-User at scipy.org
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>>
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