[SciPy-user] How does concatenate work?
dmitrey
openopt at ukr.net
Thu Jul 5 03:43:09 EDT 2007
try
b = zeros((1,4))
concatenate((a,b), 0)
array([[ 1., 2., 3., 4.],
[ 5., 6., 7., 8.],
[ 9., 10., 11., 12.],
[ 13., 14., 15., 16.],
[ 17., 18., 19., 20.],
[ 0., 0., 0., 0.]])
you may use also
concatenate((a,b.reshape(1,4)), 0)
or concatenate((a,b.reshape(1,4)))
or numpy.hstack((a,b.reshape(1,4)))
HTH,D
iCy-fLaME wrote:
> If I have a (m, n) array, is concatenate is right way to go about
> making it a (m+1, n) or (m, n+1) array?
>
> I tried the following, couldn't figure out how to do it correctly. Any
> helps are greatly appreciated.
>
>
>>>> from numpy import linspace, zeros
>>>> from numpy import concatenate
>>>>
>>>> a = linspace(1, 20, 20).reshape((5,4))
>>>> a
>>>>
> array([[ 1., 2., 3., 4.],
> [ 5., 6., 7., 8.],
> [ 9., 10., 11., 12.],
> [ 13., 14., 15., 16.],
> [ 17., 18., 19., 20.]])
>
>>>> b = zeros(4)
>>>> b
>>>>
> array([ 0., 0., 0., 0.])
>
>>>> concatenate((a,b), axis=0)
>>>>
> Traceback (most recent call last):
> File "<stdin>", line 1, in ?
> ValueError: arrays must have same number of dimensions
>
>>>> concatenate((a,b), axis=1)
>>>>
> Traceback (most recent call last):
> File "<stdin>", line 1, in ?
> ValueError: arrays must have same number of dimensions
>
>
>
>
>
> icy
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>
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