How to escape strings for re.finditer?

Roel Schroeven roel at roelschroeven.net
Tue Feb 28 04:33:20 EST 2023


Op 28/02/2023 om 3:44 schreef Thomas Passin:
> On 2/27/2023 9:16 PM, avi.e.gross at gmail.com wrote:
>> And, just for fun, since there is nothing wrong with your code, this 
>> minor change is terser:
>>
>>>>> example = 'X - abc_degree + 1 + qq + abc_degree + 1'
>>>>> for match in re.finditer(re.escape('abc_degree + 1') , example):
>> ...     print(match.start(), match.end())
>> ...
>> ...
>> 4 18
>> 26 40
>
> Just for more fun :) -
>
> Without knowing how general your expressions will be, I think the 
> following version is very readable, certainly more readable than regexes:
>
> example = 'X - abc_degree + 1 + qq + abc_degree + 1'
> KEY = 'abc_degree + 1'
>
> for i in range(len(example)):
>     if example[i:].startswith(KEY):
>         print(i, i + len(KEY))
> # prints:
> 4 18
> 26 40
I think it's often a good idea to use a standard library function 
instead of rolling your own. The issue becomes less clear-cut when the 
standard library doesn't do exactly what you need (as here, where 
re.finditer() uses regular expressions while the use case only uses 
simple search strings). Ideally there would be a str.finditer() method 
we could use, but in the absence of that I think we still need to 
consider using the almost-but-not-quite fitting re.finditer().

Two reasons:

(1) I think it's clearer: the name tells us what it does (though of 
course we could solve this in a hand-written version by wrapping it in a 
suitably named function).

(2) Searching for a string in another string, in a performant way, is 
not as simple as it first appears. Your version works correctly, but 
slowly. In some situations it doesn't matter, but in other cases it 
will. For better performance, string searching algorithms jump ahead 
either when they found a match or when they know for sure there isn't a 
match for some time (see e.g. the Boyer–Moore string-search algorithm). 
You could write such a more efficient algorithm, but then it becomes 
more complex and more error-prone. Using a well-tested existing function 
becomes quite attractive.

To illustrate the difference performance, I did a simple test (using the 
paragraph above is test text):

     import re
     import timeit

     def using_re_finditer(key, text):
         matches = []
         for match in re.finditer(re.escape(key), text):
             matches.append((match.start(), match.end()))
         return matches


     def using_simple_loop(key, text):
         matches = []
         for i in range(len(text)):
             if text[i:].startswith(key):
                 matches.append((i, i + len(key)))
         return matches


     CORPUS = """Searching for a string in another string, in a 
performant way, is
     not as simple as it first appears. Your version works correctly, 
but slowly.
     In some situations it doesn't matter, but in other cases it will. 
For better
     performance, string searching algorithms jump ahead either when 
they found a
     match or when they know for sure there isn't a match for some time 
(see e.g.
     the Boyer–Moore string-search algorithm). You could write such a more
     efficient algorithm, but then it becomes more complex and more 
error-prone.
     Using a well-tested existing function becomes quite attractive."""
     KEY = 'in'
     print('using_simple_loop:', 
timeit.repeat(stmt='using_simple_loop(KEY, CORPUS)', globals=globals(), 
number=1000))
     print('using_re_finditer:', 
timeit.repeat(stmt='using_re_finditer(KEY, CORPUS)', globals=globals(), 
number=1000))

This does 5 runs of 1000 repetitions each, and reports the time in 
seconds for each of those runs.
Result on my machine:

     using_simple_loop: [0.13952950000020792, 0.13063130000000456, 
0.12803450000001249, 0.13186180000002423, 0.13084610000032626]
     using_re_finditer: [0.003861400000005233, 0.004061900000124297, 
0.003478999999970256, 0.003413100000216218, 0.0037320000001273]

We find that in this test re.finditer() is more than 30 times faster 
(despite the overhead of regular expressions.

While speed isn't everything in programming, with such a large 
difference in performance and (to me) no real disadvantages of using 
re.finditer(), I would prefer re.finditer() over writing my own.

-- 
"The saddest aspect of life right now is that science gathers knowledge
faster than society gathers wisdom."
         -- Isaac Asimov



More information about the Python-list mailing list