How to 'ignore' an error in Python?

[Chris Green]

I'm sure I'm missing something obvious here but I can't see an elegant
way to do this.  I want to create a directory, but if it exists it's
not an error and the code should just continue.

So, I have:-

    for dirname in listofdirs:
        try:
            os.mkdir(dirname)
        except FileExistsError:
            # so what can I do here that says 'carry on regardless'
        except:
            # handle any other error, which is really an error

        # I want code here to execute whether or not dirname exists


Do I really have to use a finally: block?  It feels rather clumsy.

I suppose I could test if the directory exists before the os.mkdir()
but again that feels a bit clumsy somehow.

I suppose also I could use os.mkdirs() with exist_ok=True but again
that feels vaguely wrong somehow.


-- 
Chris Green
·