How to test characters of a string

2QdxY4RzWzUUiLuE at potatochowder.com 2QdxY4RzWzUUiLuE at potatochowder.com
Wed Jun 8 13:14:29 EDT 2022


On 2022-06-08 at 08:07:40 -0000,
De ongekruisigde <ongekruisigde at news.eternal-september.org> wrote:

> Depending on the problem a regular expression may be the much simpler
> solution. I love them for e.g. text parsing and use them all the time.
> Unrivaled when e.g. parts of text have to be extracted, e.g. from lines
> like these:
> 
>   root:x:0:0:System administrator:/root:/run/current-system/sw/bin/bash
>   dhcpcd:x:995:991::/var/empty:/run/current-system/sw/bin/nologin
>   nm-iodine:x:996:57::/var/empty:/run/current-system/sw/bin/nologin
>   avahi:x:997:996:avahi-daemon privilege separation user:/var/empty:/run/current-system/sw/bin/nologin
>   sshd:x:998:993:SSH privilege separation user:/var/empty:/run/current-system/sw/bin/nologin
>   geoclue:x:999:998:Geoinformation service:/var/lib/geoclue:/run/current-system/sw/bin/nologin
> 
> Compare a regexp solution like this:
> 
>   >>> g = re.search(r'([^:]*):([^:]*):(\d+):(\d+):([^:]*):([^:]*):(.*)$' , s)
>   >>> print(g.groups())
>   ('geoclue', 'x', '999', '998', 'Geoinformation service', '/var/lib/geoclue', '/run/current-system/sw/bin/nologin')
> 
> to the code one would require to process it manually, with all the edge
> cases. The regexp surely reads much simpler (?).

Uh...

    >>> import pwd # https://docs.python.org/3/library/pwd.html
    >>> [x for x in pwd.getpwall() if x[0] == 'geoclue']
    [pwd.struct_passwd(pw_name='geoclue', pw_passwd='x', pw_uid=992, pw_gid=992, pw_gecos='Geoinformation service', pw_dir='/var/lib/geoclue', pw_shell='/sbin/nologin')]


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