How to convert a raw string r'\xdd' to '\xdd' more gracefully?

[Thomas Passin]

The original post started out with r'\x0a' but then talked about '\xdd'. 
  I assumed that there was a pattern here, a raw string containing "\x" 
and two more characters, and made a suggestion for converting any string 
with that pattern.  But the OP was very unclear what the task really 
was, so here we all are, making a variety of guesses.

On 12/8/2022 8:23 AM, Weatherby,Gerard wrote:
> I’m not understanding the task. The sample code given is converting the input r’\x0a’ to a newline, it appears.
> 
> 
> import re
> 
> 
> def exam(z):
>      print(f"examine {type(z)} {z}")
>      for c in z:
>          print(f"{ord(c)} {c}")
> 
> s0 = r'\x0a'
> 
> def to1byte(matchobj):
>      return chr(int('0x' + matchobj.group(1), 16))
> s1 = re.sub(r'\\x([0-9a-fA-F]{2})', to1byte, s0)
> exam(s0)
> exam(s1)
> 
> ---
> examine <class 'str'> \x0a
> 92 \
> 120 x
> 48 0
> 97 a
> examine <class 'str'>
> 
> 10
> 
> From: Python-list <python-list-bounces+gweatherby=uchc.edu at python.org> on behalf of Jach Feng <jfong at ms4.hinet.net>
> Date: Wednesday, December 7, 2022 at 9:27 PM
> To: python-list at python.org <python-list at python.org>
> Subject: Re: How to convert a raw string r'xdd' to 'xdd' more gracefully?
> *** Attention: This is an external email. Use caution responding, opening attachments or clicking on links. ***
> 
> Peter Otten 在 2022年12月8日 星期四清晨5:17:59 [UTC+8] 的信中寫道：
>> On 07/12/2022 03:23, Jach Feng wrote:
>>> s0 = r'\x0a'
>>> At this moment it was done by
>>>
>>> def to1byte(matchobj):
>>> ....return chr(int('0x' + matchobj.group(1), 16))
>>> s1 = re.sub(r'\\x([0-9a-fA-F]{2})', to1byte, s0)
>>>
>>> But, is it that difficult on doing this simple thing?
>>>>> import codecs
>>>>> codecs.decode(r"\x68\x65\x6c\x6c\x6f\x0a", "unicode-escape")
>> 'hello\n'
> Thank you. What I really want to handle is to any r'\xdd'. The r'\x0a' is for example. Sorry, didn't describe it clearly:-)
> --
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