Printing Unicode strings in a list

[Vlastimil Brom]

čt 28. 4. 2022 v 13:33 odesílatel Stephen Tucker
<stephen_tucker at sil.org> napsal:
>
> Hi PythonList Members,
>
> Consider the following log from a run of IDLE:
>
> ==================
>
> Python 2.7.10 (default, May 23 2015, 09:40:32) [MSC v.1500 32 bit (Intel)]
> on win32
> Type "copyright", "credits" or "license()" for more information.
> >>> print (u"\u2551")
> ║
> >>> print ([u"\u2551"])
> [u'\u2551']
> >>>
>
> ==================
>
> Yes, I am still using Python 2.x - I have good reasons for doing so and
> will be moving to Python 3.x in due course.
>
> I have the following questions arising from the log:
>
> 1. Why does the second print statement not produce [ ║]  or ["║"] ?
>
> 2. Should the second print statement produce [ ║]  or ["║"] ?
>
> 3. Given that I want to print a list of Unicode strings so that their
> characters are displayed (instead of their Unicode codepoint definitions),
> is there a more Pythonic way of doing it than concatenating them into a
> single string and printing that?
>
> 4. Does Python 3.x exhibit the same behaviour as Python 2.x in this respect?
>
> Thanks in anticipation.
>
> Stephen Tucker.
> --
> https://mail.python.org/mailman/listinfo/python-list

Hi,
I'm not sure, whether I am not misunderstanding the 4th question or
the answers to it (it is not clear to me, whether the focus is on
character printing or the quotation marks...);
in either case, in python3 the character glyphs are printed in these
cases, instead of the codepoint number notation, cf.:
==================
Python 3.8.10 (tags/v3.8.10:3d8993a, May  3 2021, 11:48:03) [MSC v.1928 64 bit (
AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> print ([u"\u2551"])
['║']
>>>
>>> print([u"\u2551"])
['║']
>>> print("\u2551")
║
>>> print("║")
║
>>> print(repr("\u2551"))
'║'
>>> print(ascii("\u2551"))
'\u2551'
>>>
==================

(Even the redundant u prefix from your python2 sample is apparently
accepted, maybe for compatibility reasons.)

hth,
   vbr