on writing a while loop for rolling two dice

[Hope Rouselle]

Chris Angelico <rosuav at gmail.com> writes:

> On Mon, Aug 30, 2021 at 11:13 PM David Raymond <David.Raymond at tomtom.com> wrote:
>>
>> > def how_many_times():
>> >   x, y = 0, 1
>> >   c = 0
>> >   while x != y:
>> >     c = c + 1
>> >     x, y = roll()
>> >   return c, (x, y)
>>
>> Since I haven't seen it used in answers yet, here's another option using our new walrus operator
>>
>> def how_many_times():
>>     roll_count = 1
>>     while (rolls := roll())[0] != rolls[1]:
>>         roll_count += 1
>>     return (roll_count, rolls)
>>
>
> Since we're creating solutions that use features in completely
> unnecessary ways, here's a version that uses collections.Counter:
>
> def how_many_times():
>     return next((count, rolls) for count, rolls in
> enumerate(iter(roll, None)) if len(Counter(rolls)) == 1)
>
> Do I get bonus points for it being a one-liner that doesn't fit in
> eighty characters?

Lol.  You do not.  In fact, this should be syntax error :-D --- as I
guess it would be if it were a lambda expression?