why sqrt is not a built-in function?

[Ethan Furman]

On 1/14/21 11:06 AM, Eli the Bearded wrote:

> "There should be one-- and preferably only one --obvious way to do it."
> 
> Meanwhile, Alan Gauld pointed out:
> 
>    AG> because pow() is a builtin function and
>    AG> root = pow(x,0.5)
>    AG> is the same as
>    AG> root = math.sqrt(x)
> 
> Plus the ** operation ("root = x ** 0.5"), that's now three ways.

Yes, but which of those is obvious?

--
~Ethan~