primitive password cracker

[Bischoop]

On 2021-01-07, David Raymond <David.Raymond at tomtom.com> wrote:
> I think you might want to check out itertools.product()
> https://docs.python.org/3.9/library/itertools.html#itertools.product


Thanks David for contribution I find it very convenient but not knowing
how to solve solution without itertools for:
for a i xxxx:
	for b in xxxx:
		for c in xxxx:
			for d in xxxx:
				

doesn't give me a peace.

--
Thanks