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Le 05/08/2021 à 11:40, Jach Feng a écrit :
> I want to distinguish between numbers with/without a dot attached:
> 
>>>> text = 'ch 1. is\nch 23. is\nch 4 is\nch 56 is\n'
>>>> re.compile(r'ch \d{1,}[.]').findall(text)
> ['ch 1.', 'ch 23.']
>>>> re.compile(r'ch \d{1,}[^.]').findall(text)
> ['ch 23', 'ch 4 ', 'ch 56 ']
> 
> I can guess why the 'ch 23' appears in the second list. But how to get rid of it?
> 
> --Jach
> 

 >>> import re

 >>> text = 'ch 1. is\nch 23. is\nch 4 is\nch 56 is\n'

 >>> re.findall(r'ch \d+\.', text)
['ch 1.', 'ch 23.']

 >>> re.findall(r'ch \d+(?!\.)', text)   # (?!\.) for negated look ahead
['ch 2', 'ch 4', 'ch 56']