How to cover connection exception errors, and exit

[Peter Otten]

dcwhatthe at gmail.com wrote:

> Hi,
> 
> I've tried urllib, requests, and some other options.  But I haven't found
> a way to trap certain urls that aren't possible to connect from, outside
> the office.  In those cases, I need to just output an error.
> 
> 
> So, the following code will cover the 404s and similar errors for most of
> the problem IPs and urls.  But for these particular problem urls, while
> debugging it keeps transferring control to adapters.py, and outputting
> 
>      requests.exceptions.ConnectionError:
>      HTTPSConnectionPool(host='xxxxxxx.state.gov', port=443): Max retries
>      exceeded with url: /xxx/xxx/xxx....(Caused by
>      NewConnectionError('<urllib3.connection.VerifiedHTTPSConnection
>      object at 0x03934538>: Failed to establish a new connection: [Errno
>      11001] getaddrinfo failed'))
> 
> 
> How do I trap this error, without invoking adapters.py?

If requests catches the error -- I don't know. 

If you fail to catch the error in your code -- what happens if you use a 
bare except? Like

try:
    ...  # your code
except:
    print(sys.exc_info())

This should print the type of exception you need to catch.


> I've tried many things, but the most recent is this code, from the web:
> 
> 
> 
>     try:
>         r = requests.get(url,timeout=3)
>         r.raise_for_status()
>     except requests.exceptions.HTTPError as errh:
>         print ("Http Error:",errh)
>     except requests.exceptions.ConnectionError as errc:
>         print ("Error Connecting:",errc)
>     except requests.exceptions.Timeout as errt:
>         print ("Timeout Error:",errt)
>     except requests.exceptions.RequestException as err:
>         print ("OOps: Something Else",err)
>         
> 
> It seems like the error should be trapped by the exception above
> requests.exceptions.ConnectionError, but instead its' hitting adapters.py.