braket an matrix in python

[Parisa Ch]

On Monday, February 3, 2020 at 9:46:43 PM UTC+3:30, Peter Otten wrote:
> Parisa Ch wrote:
> 
> > x=np.linspace(0,2*math.pi,n)
> > n=len(x)
> > r=int(math.ceil(f*n))
> > h=[np.sort(np.abs(x-x[i]))[r] for i in range(n)]
> > 
> > this is part of a python code. the last line is confusing? x is a matrix
> > and x[i] is a number. how  calculate x-x[i] for each i?
> >  why the put r in [] ?
> 

thank you so much 
> Brake it appart:
> 
> y = x - x[i]  # the numpy feature that makes that possible is called
>               # "broadcasting"
> 
> subtracts the value x[i] from every entry in the vector x
> 
> z = np.abs(y)
> 
> calculates the absolute value of every entry in y.
> 
> t = np.sort(z)
> 
> sorts the values in z and finally, assuming r is an integer,
> 
> u = t[r]  
> 
> looks up a single scalar in the vector.
> 
> The enclosing "list comprehension" [expr for item in iterable] builds a list 
> of n values calculated as sketched above.