dict.get(key, default) evaluates default even if key exists
Peter J. Holzer
hjp-python at hjp.at
Thu Dec 17 06:40:49 EST 2020
On 2020-12-17 12:16:29 +0100, jak wrote:
> print(_ if d.get('a', None) is not None else get_default())
That doesn't work:
>>> print(_ if d.get('a', None) is not None else get_default())
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: name '_' is not defined
But this works:
>>> print(_ if (_ := d.get('a', None)) is not None else get_default())
1
(I would prefer ChrisA's solution, though.)
hp
--
_ | Peter J. Holzer | Story must make more sense than reality.
|_|_) | |
| | | hjp at hjp.at | -- Charles Stross, "Creative writing
__/ | http://www.hjp.at/ | challenge!"
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