dict.get(key, default) evaluates default even if key exists

[Mark Polesky]

I see. Perhaps counterintuitive, but implemented consistently. Add it to the list of gotchas, I guess.

By the way... four helpful responses in under an hour, very impressive. Nice community here. Thanks to all who answered.

Mark






On Tuesday, December 15, 2020, 11:05:10 AM PST, Serhiy Storchaka <storchaka at gmail.com> wrote: 





15.12.20 19:07, Mark Polesky via Python-list пише:

> # Running this script....
> 
> D = {'a':1}
> def get_default():
>     print('Nobody expects this')
>     return 0
> print(D.get('a', get_default()))
> 
> # ...generates this output:
> 
> Nobody expects this
> 1
> 
> ###
> 
> Since I'm brand new to this community, I thought I'd ask here first... Is this worthy of a bug report?  This behavior is definitely unexpected to me, and I accidentally coded an endless loop in a mutual recursion situation because of it.  Calling dict.get.__doc__ only gives this short sentence: Return the value for key if key is in the dictionary, else default.  Nothing in that docstring suggests that the default value is evaluated even if the key exists, and I can't think of any good reason to do so.
> 
> Am I missing something?


You are missed that expressions for function arguments are always
evaluated before passing their values to a function. This is expected
behavior, and I can't remember any programming language in which it's
different.

So dict.get() returns the value of argument default, which is computed
by calling function get_default() before calling dict.get().

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