To check if number is in range(x,y)

[Tim Chase]

On 2020-12-12 15:12, Bischoop wrote:
> I need to check if input number is 1-5. Whatever I try it's not
> working. Here are my aproaches to the problem: https://bpa.st/H62A
> 
> What I'm doing wrong and how I should do it?

A range is similar to a list in that it contains just the numbers
listed:

  >>> r = range(10)
  >>> 2 in r
  True
  >>> 2.5 in r
  False
  >>> r = range(1, 10, 2)
  >>> 2 in r
  False
  >>> list(r)
  [1, 3, 5, 7, 9]

It also doesn't automatically convert from the string inputs you're
getting from the input() function:

  >>> s = "5"
  >>> s in r
  False
  >>> int(s) in r
  True

Additionally, note that the endpoint of the range is exclusive so

  >>> r = range(1, 10)
  >>> 10 in r
  False
  >>> list(r)
  [1, 2, 3, 4, 5, 6, 7, 8, 9]

If you want numeric-range checks, Python provides the lovely
double-comparison syntax:

  >>> x = 5
  >>> 2 < x < 10
  True
  >>> x = 5.5
  >>> 2 < x < 10
  True
  >>> s = "5"
  >>> 2 < s < 10
  Traceback…
  >>> 2 < int(s) < 10
  True

Hopefully this gives you the hints that you need to troubleshoot.

-tkc