Function returns old value

[Bischoop]

On 2020-12-12, Joe Pfeiffer <pfeiffer at cs.nmsu.edu> wrote:
> Bischoop <Bischoop at vimart.net> writes:
>
>> I've function asking question and comparing it, if is not matching 'yes'
>> it does call itself to ask question again. The problem is that when
>> function is called second time it returns old value or with additional
>> else statement it returns none.
>>
>> Code: https://bpa.st/KVGA
>
> It calls itself again, but what does it return in that case?

I've stated it returns old value that I've input first time, anyway
output is also inluded in a paste but since you've asked:

def question():
    ask = input("Are you OK?:").lower()
        if ask != 'yes':
	        question()
		    return ask

		    print (question())

		    #output:
		    Are you OK?:no
		    Are you OK?:no
		    Are you OK?:yes
		    no

		    ---------------------------------------
		    #Another way with 'elif' statment returns none


		    def question():
		        ask = input("Are you OK?:").lower()
			    if ask != 'yes':
			            question()
				        elif ask == 'yes':
					        return ask

						print (question())

						#output:
						Are you OK?:no
						Are you OK?:yes
						None

						#Tried also nested
						functions, same results:

						def question():
						    ask = input("Are you
						    OK?:").lower()

						        def
							check_question(n):
							        if ask
								!=
								'yes':
								            question()
									            else:
										                return
												ask

												    m
												    =
												    check_question(ask)
												        print
													(m)
													question()

													#output:
													Are
													you
													OK?:no
													Are
													you
													OK?:yes
													None

													Process
													finished
													with
													exit
													code
													0