Why __hash__() does not return an UUID4?

[Richard Damon]

On 8/26/20 5:13 PM, 2QdxY4RzWzUUiLuE at potatochowder.com wrote:
> On 2020-08-26 at 22:10:26 +0200,
> Marco Sulla <Marco.Sulla.Python at gmail.com> wrote:
>
>> As title ...
> Assuming that the title appears prominently with the content of your
> email.  For the rest of us:
>
>     Why __hash__() does not return an UUID4?
>
>> ... The reasons that came in my mind are:
>>
>> 1. speed
>> 2. security
> Correctness?
>
> Why would __hash__() return a random number?  An important property of
> hashes is that if x == y, then hash(x) == hash(y).  If hash(x) and
> hash(y) were random numbers, then how would this property be maintained?
>
> Or do UUID4 mean something else to you than a random number?

Looking up which UUID type 4 is, yes it is a random number, so could
only be applicable for objects that currently return id(), which could
instead make id() be a UUID4 (and save it in the object, increasing its
side)

-- 
Richard Damon