How do I do this in Python 3 (string.join())?

[D'Arcy Cain]

On 2020-08-26 09:22, Chris Green wrote:
> I have the following line in Python 2:-
> 
>     msgstr = string.join(popmsg[1], "\n")      # popmsg[1] is a list containing the lines of the message
> 
> ... so I changed it to:-
> 
>     s = "\n"
>     msgstr = s.join(popmsg[1])      # popmsg[1] is a list containing the lines of the message
> 
> However this still doesn't work because popmsg[1] isn't a list of
> strings, I get the error:-
> 
>     TypeError: sequence item 0: expected str instance, bytes found
> 
> So how do I do this?  I can see clumsy ways by a loop working through
> the list in popmsg[1] but surely there must be a way that's as neat
> and elegant as the Python 2 way was?

Well, the simple fix is to set s to b"\n" but that may not solve all of your
problems.  The issue is that popmsg[1] is a list of bytes.  You probably
want a list of strings.  I would look further back and think about getting a
list of strings in the first place.  Without knowing how popmsg was created
we can't tell you how to do that.

Of course, if a bytes object is what you want then the above will work.  You
can also convert to string after the join.

Cheers.

-- 
D'Arcy J.M. Cain
Vybe Networks Inc.
A unit of Excelsior Solutions Corporation - Propelling Business Forward
http://www.VybeNetworks.com/
IM:darcy at VybeNetworks.com VoIP: sip:darcy at VybeNetworks.com

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