What variable type is returned from Open()?

[dcwhatthe at gmail.com]

On Wednesday, April 15, 2020 at 10:10:31 AM UTC-4, Souvik Dutta wrote:
> _io.TextIOWrapper
> 
> On Wed, 15 Apr, 2020, 7:30 pm , <dcwhatthe> wrote:
> 
> > Hi,
> >
> >
> > As much as possible, I make use of optional type hints.  So if I know a
> > function returns an integer, then I use
> >
> >
> > this_number_i : int = GetThisNumber()
> >
> >
> > But there's no 'file' type, so I'm not sure what to use as the type for
> > the return value of an Open() function.
> >
> >
> > config_file : file = open(config_file_s, "r")
> >
> >
> > What type of variable should config_file (above) be declared as?
> >
> > --
> > https://mail.python.org/mailman/listinfo/python-list
> >

So you're saying this is a type _io.TextIOWrapper?  This type doesn't show up, on the hint listbox (I'm using Wing IDE).  So if I type var_file : _io, it doesn't show anything.

Maybe I don't understand what you're saying.