Exercize to understand from three numbers which is more high

[Ian Clark]

threw this together, let me know what you think


num_list=[]
name_list =
['first','second','third','fourth','fifth','sixth','seventh','eighth','ninth','tenth']
name_it = name_list.pop(0)

while len(num_list) < 3:
 try:
  num_list.append( int( input(f"Insert the {name_it} number: ")))

 except ValueError:
  print('Not a number, try again!')
 else:
  name_it = name_list.pop(0)

print(f"Max number is: {sorted(num_list)[-1]}")

On Mon, Jan 28, 2019 at 1:58 AM Frank Millman <frank at chagford.com> wrote:

> "^Bart"  wrote in message news:q2mghh$ah6$1 at gioia.aioe.org...
> >
> > > 1. The last two lines appear to be indented under the 'if number3 < '
> > > line. I think you want them to be unindented so that they run every
> > > time.
> >
> > I'm sorry but I didn't completely understand what you wrote about the
> last
> > two lines, please could you write how my code could be fixed?
> >
>
> The last four lines of your program look like this -
>
> if number3 < number2 and number3 < number1:
>      numbermin = number3
>
>      print("Number min is: ",numbermin)
>
>      numbermiddle = (number1+number2+number3)-(numbermax+numbermin)
>
>      print("Number middle is: ",numbermiddle)
>
> The last three lines all fall under the 'if number3 < number2' line, so
> they
> will only be executed if that line evaluates to True.
>
> I think that you want the last two lines to be executed every time. If so,
> they should be lined up underneath the 'if', not the 'print'.
>
> >
> > >     if a == 1:
> > >         do something
> > >     elif a == 2:
> > >         do something else
> >
> > Finally I understood the differences between if and elif! Lol! :D
> >
>
> It is actually short for 'else if', but I guess it is not obvious if you
> have not seen it before!
>
> Frank
>
>
> --
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>