Exercize to understand from three numbers which is more high

[^Bart]

> You have got to a starting point - you have three numbers. Good.
> 
> Where do you do go from here?
> 
> I would start with two of the numbers, and work out which one is higher.

# SOLVED!!!
number1 = int( input("Insert the first number: "))

number2 = int( input("Insert the second number: "))

number3 = int( input("Insert the third number: "))

numbermax = number1

numbermiddle = number2

numbermin = number3

if number2 > number1 and number2 > number3:
     numbermax = number2

     print("Number max is: ",numbermax)

if number1 > number2 and number1 > number3:
     numbermax = number1

     print("Number max is: ",numbermax)

if number3 > number2 and number3 > number1:
     numbermax = number3

     print("Number max is: ",numbermax)

if number2 < number1 and number2 < number3:
     numbermin = number2

     print("Number min is: ",numbermin)

if number1 < number2 and number1 < number3:
     numbermin = number1

     print("Number min is: ",numbermin)

if number3 < number2 and number3 < number1:
     numbermin = number3

     print("Number min is: ",numbermin)

     numbermiddle = (number1+number2+number3)-(numbermax+numbermin)

     print("Number middle is: ",numbermiddle)

Maybe it's not the best way to do it but at this time in our course we 
should try to solve problems just by using few things like if, else, 
etc. I know there's also min or max but before to use them we must 
understand if else! :)

> Frank Millman

Thank you very much, you helped me to power on my brain! :D
^Bart