how to exit from a nested loop in python

Kaka kusalakalani at gmail.com
Fri Feb 8 01:45:07 EST 2019


for i  in range(len(A.hp)):

        for j in range(len(run_parameters.bits_Mod)):
         req_slots[j] = math.ceil((A.T[i])

         for g in Temp[i]["Available_ranges"][j]:
          for s in range(g[0], g[-1]):
              if (s+req_slots[j]-1) <= g[-1]:
                 if (Temp[i]['cost'][j] <= (run_parameters.PSD):  ------ When this condition is true i want to break the nested loop and start from the begining
                   served_count +=1
                   A.T[i]["First_index"]= s
                   A.T[i]["Last_index"]= s+req_slots[j]-1
                   A.T[i]["Status"]= 1
                   A.T[i]["Selected_MOD"] = j
                   break

I have this code. When the last "if" condition is satisfied, i want to break all the loops and start the nested loop for next i. else, the loop should continue.  

can anyone help me?



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