[SOLVED] Re: Compare zip lists where order is important

[Peter Otten]

Sayth Renshaw wrote:

> On Thursday, 29 August 2019 20:33:46 UTC+10, Peter Otten  wrote:
>> Sayth Renshaw wrote:
>> 
>> > will find the added
>> > pairs, but ignore the removed ones. Is that what you want?
>> > 
>> > Yes, I think. I want to find the changed pairs. The people that moved
>> > team numbers.
>> 
>> To find the people that moved team numbers I would tear the pairs apart.
>> Like:
>> 
>> >>> people = ["Tim","Bill","Sally","Ally","Fred","Fredricka"]
>> >>> team_number = [1,1,2,2,3,3]
>> >>> shuffle_people = ["Fredricka","Bill","Sally","Tim","Ally","Fred"]
>> >>> shuffle_team_number = [1,1,2,2,3,3]
>> >>> old = dict(zip(people, team_number))
>> >>> new = dict(zip(shuffle_people, shuffle_team_number))
>> >>> for name in old.keys() & new.keys():
>> ...     old_team = old[name]
>> ...     new_team = new[name]
>> ...     if old_team != new_team:
>> ...         print(name, "went from", old_team, "to", new_team)
>> ...
>> Tim went from 1 to 2
>> Fredricka went from 3 to 1
>> Ally went from 2 to 3
> 
> The reason I opted away from Dictionaries is if there was a team with
> people with same name. Then the keys would be the same.
> 
> So if Sally left and team 2 had one Tim move in and a new Tim start.
> shuffle_people = ["Fredricka","Bill","Tim","Tim","Ally","Fred"]
> shuffle_team_number = [1,1,2,2,3,3]
> 
> becomes
> {'Fredricka': 1, 'Bill': 1, 'Tim': 2, 'Ally': 3, 'Fred': 3}
> 
> This still appears to work but is wrong.
> 
> for name in old.keys()& new.keys():
>     old_team = old[name]
>     new_team = new[name]
>     if old_team != new_team:
>         print(name, "went from", old_team, "to", new_team)
> Ally went from 2 to 3
> Tim went from 1 to 2
> Fredricka went from 3 to 1
> 
> But I guess in reality I would use a UID and then look up the UID in a
> list or database.

It doesn't matter how you calculate the team changes; you always have to 
ensure unique players.