Calling an instance method defined without any 'self' parameter

[Bob van der Poel]

On Thu, Oct 4, 2018 at 1:25 AM Ibrahim Dalal <ibrahimhusain007 at gmail.com>
wrote:

> class A:
>     def foo():
>         print 'Hello, world!'
>
> a = A()print A.foo       # <unbound method A.foo>print a.foo       #
> <bound method A.foo of <__main__.A instance at 0x7efc462a7830>>print
> type(A.foo) # <type 'instancemethod'>
> a.foo()           # TypeError: foo() takes no arguments (1 given)
> A.foo()           # TypeError: unbound method foo() must be called
> with A instance as first argument (got nothing instead)
>
>
> Clearly, foo is an instance method. I know one should use @staticmethod for
> declaring a method static. The question here is, given the above code, is
> there any way to call foo?
>
> Python 2.7
>
>
> Thanks,
> --
> https://mail.python.org/mailman/listinfo/python-list
>

Use the magic of staticmethod :)

class A:
   @staticmethod
   def foo():
        ... do foo stuff


Hope this helps.

-- 

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