why does list's .remove() does not return an object?

[Abdur-Rahmaan Janhangeer]

x = [0,1]
x.remove(0)
new_list = x

instead i want in one go

x = [0,1]
new_list = x.remove(0) # here a way for it to return the modified list by
adding a .return() maybe ?

Abdur-Rahmaan Janhangeer
https://github.com/Abdur-rahmaanJ

On Thu, 17 May 2018, 19:54 Alexandre Brault, <abrault at mapgears.com> wrote:

>
> On 2018-05-17 11:26 AM, Abdur-Rahmaan Janhangeer wrote:
> > I don't understand what this would return? x? You already have x.  Is it
> > meant to make a copy? x has been mutated, so I don't understand the
> benefit
> > of making a copy of the 1-less x.  Can you elaborate on the problem you
> are
> > trying to solve?
> >
> > --Ned.
> >
> >
> > assignment to another var
> >
> You already have access to the list before removal, the list after
> removal and the element to be removed.
>
> Do need a copy of the list before removing x?
> >>> old_list = list[:]
> >>> list.remove(x)
>
> Do you need the list after removing x?
> >>> list.remove(x)  # list is the modified list
>
> Do you need x?
> >>> list.remove(x)  # x is x
>
> What else would need to be assigned to another var?
> --
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>