Simplest way to clobber/replace one populated directory with another?

[Michael F. Stemper]

On 2018-05-15 11:37, Travis Griggs wrote:
> I have a directory structure that might look something like:
> 
>      Data
>          Current
>              A
>              B
>              C
>          Previous
>              A
>              X
> 
> In as simple/quick a step as possible, I want to rename Current as Previous including the contents and wiping out the original such that it is now:
> 
>      Data
>          Previous
>              A
>              B
>              C

Is this what you need?

username at hostname$ ll */*
-rw-rw-r-- 1 username username  7 May 16 15:54 Current/1
-rw-rw-r-- 1 username username  7 May 16 15:54 Current/2
-rw-rw-r-- 1 username username 11 May 16 15:54 Current/3
-rw-rw-r-- 1 username username 18 May 16 15:55 Previous/1
-rw-rw-r-- 1 username username 18 May 16 15:55 Previous/2
-rw-rw-r-- 1 username username 14 May 16 15:55 Previous/3
username at hostname$ python
Python 2.7.12 (default, Dec  4 2017, 14:50:18)
[GCC 5.4.0 20160609] on linux2
Type "help", "copyright", "credits" or "license" for more information.
 >>> import shutil, os
 >>> shutil.rmtree("Previous")
 >>> os.rename("Current","Previous")
 >>>
username at hostname$ ll */*
-rw-rw-r-- 1 username username  7 May 16 15:54 Previous/1
-rw-rw-r-- 1 username username  7 May 16 15:54 Previous/2
-rw-rw-r-- 1 username username 11 May 16 15:54 Previous/3
username at hostname$

> (I am running on Linux)

If you can do this from a bash script rather than a python program, you
could just do:

#!/bin/bash
rm -r Previous
mv Previous Current

-- 
Michael F. Stemper
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