Quick survey: locals in comprehensions (Python 3 only)

[Chris Angelico]

On Tue, Jun 26, 2018 at 8:04 PM, Antoon Pardon <antoon.pardon at vub.be> wrote:
> On 26-06-18 11:22, Steven D'Aprano wrote:
>> On Tue, 26 Jun 2018 10:20:38 +0200, Antoon Pardon wrote:
>>
>>>> def test():
>>>>     a = 1
>>>>     b = 2
>>>>     result = [value for key, value in locals().items()]
>>>>     return result
>> [...]
>>
>>> I would expect an UnboundLocalError: local variable 'result' referenced
>>> before assignment.
>> Well, I did say that there's no right or wrong answers, but that
>> surprises me. Which line do you expect to fail, and why do you think
>> "result" is unbound?
>
> I would expect the third statement to fail because IMO we call the locals
> function before result is bound. But result is a local variable so the
> locals function will try to reference it, hence the UnboundLocalError.

Would you expect the same behaviour from this function?

def test():
    a = 1
    b = 2
    result = locals()
    return result

ChrisA