Regex to extract multiple fields in the same line

[Ganesh Pal]

 Hi Team,

I wanted to parse a file and extract few feilds that are present after "="
in a text file .


Example , form  the below line I need to extract the values present after
--struct =, --loc=, --size= and --log_file=

Sample input

line = '06/12/2018 11:13:23 AM python toolname.py  --struct=data_block
--log_file=/var/1000111/test18.log --addr=None --loc=0 --mirror=10
--path=/tmp/data_block.txt size=8'


Expected output

data_block
/var/1000111/test18.log
0
8


Here is my sample code , its still not complete ,  I wanted to use regex
and find and extract all the fields after " =", any suggestion or
alternative way to optimize this further


import re
line = '06/12/2018 11:13:23 AM python toolname.py  --struct=data_block
--log_file=/var/1000111/test18.log --addr=None --loc=0 --mirror=10
--path=/tmp/data_block.txt size=8'

r_loc = r"--loc=(\d+)"
r_struct = r'--struct=(\w+)'

if re.findall(r_loc, line):
   print re.findall(r_loc, line)

if re.findall(r_struct, line):
   print re.findall(r_struct, line)


root at X1:/# python regex_02.py
['0']
['data_block']


I am a  Linux  user with python 2.7


Regards,
Ganesh