Compression of random binary data

[Chris Angelico]

On Sun, Jan 28, 2018 at 4:26 PM,  <pendrysammuel at gmail.com> wrote:
> If it is then show him this
>
> 387,420,489
> =
> 00110011 00111000 00110111 00101100 00110100 00110010 00110000 00101100 00110100 00111000 00111001
>
> 9^9 = ⬇️ (^ = to the power of)
> = 387,420,489
>
> But
>
> 9^9
> =
> 00111001 01011110 00111001

I have no idea what you're responding to or how this has anything to
do with the thread you're replying to, but I would advise you to look
into the difference between exponentiation and exclusive-or. Even so,
I don't know what result you got.

ChrisA