Printing a Chunk Of Words

[Matt Wheeler]

With deepest apologies to all involved...

On Tue, 26 Sep 2017 at 08:42 Gregory Ewing <greg.ewing at canterbury.ac.nz>
wrote:

> Ben Bacarisse wrote:
> > Think functional!  This is 257 characters:
>
> 250 chars, 17 shorter than the text it produces:
>
> a=[];o=[];n=[];A=list.append
> for b in range(3,-1,-1):
>   x=bool(b>>1);y=bool(b&1);A(a,"%s and %s is %s"%(x,y,x and y));A(o,"%s or
> %s is
> %s"%(x,y,x or y))
>   if x:A(n,"not %s is %s"%(y,not y))
> print("    Boolean Operators\n"+"-"*24+"\n"+"\n".join(a+o+n))
>

Cutting the same (quite reasonable) corners as you, I've got it down 212
characters:

t,f,a,o,n='True','False','and','or','not'
l=["     Boolean Operators\n"+"-"*24]
for x in [(l,p,r)for p in(a,o)for l in(t,f)for r in(t,f)]+[(n,t),(n,f)]:x='
'.join(x);l+=[x[0].upper()+x[1:]+" is "+str(eval(x))]
for i in 12,9,5,0:l.insert(i,'')
print('\n'.join(l))

Reproducing the original string exactly the best I've managed is 260:

t,f,a,o,n='True','False','and','or','not'
l=["     Boolean Operators\n"+"-"*24]
for x in [(l,p,r)for p in(a,o)for l in(t,f)for r in(t,f)]+[(n,t),(n,f)]:x='
'.join(x);l+=[x[0].upper()+x[1:]+" is "+str(eval(x))]
for i in 12,9,5,0:l.insert(i,'')
print('\n'.join(l))

-- 

--
Matt Wheeler
http://funkyh.at