Python string replace the values

[Ganesh Pal]

> (I assume that in your example "a0000" and "aa" => c00aa,  that really
should have been   a00aa)

Yes , thanks for noticing.

On Fri, Sep 1, 2017 at 11:18 PM, Irv Kalb <Irv at furrypants.com> wrote:

>
> > On Sep 1, 2017, at 10:13 AM, Ganesh Pal <ganesh1pal at gmail.com> wrote:
> >
> > In the fixed length string i.e "a0000",last 4 bits i.e "0000" should be
> > replaced by the user provided value ( the value is between 0001 + f f f
> f )
> > . I intend to form  final_string  using a fixed_string and an user
> provided
> > user_string
> >
> >
> > Example:
> >
> > fixed_string = "a0000"
> > user_string ='1'
> >
> > final string = fixed_string  and  user_string
> >
> > Example :
> >
> >  "a0000" and "1" => a0001
> >
> >  "a0000" and "aa" => c00aa
> >
> >
> > PS :  "and" this is not logical and it's just for example
> >
> > If I concatenation using + or +=  or it's append the value at the end of
> > the string
> >
> >>>> "a0000" + "1"    ===> expected was a0001
> > 'a00001'
> >
> >
> >
> > I am on python 2.7 and Linux ,  any ideas that you recommend  to handle
> > this
> >
> >
> > Regards,
> > Ganesh
> >
>
> Here's a little function that should it it for you.
>
> (I assume that in your example "a0000" and "aa" => c00aa,  that really
> should have been   a00aa)
>
> This should work for any size fixed_string and user_string (as long as the
> user_string is not longer than the fixed_string)
>
> def mergeStrings(fixed_string, user_string):
>     nCharsInFixedString = len(fixed_string)
>     nCharsInUserString = len(user_string)
>
>     nCharsToGetFromFixedString = nCharsInFixedString - nCharsInUserString
>
>     finalString = fixed_string[:nCharsToGetFromFixedString] + user_string
>
>     return finalString
>
> Irv
>
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>