Is there a function of ipaddress to get the subnet only from input like 192.168.1.129/25

[Daniel Flick]

On Tuesday, October 17, 2017 at 8:24:52 PM UTC-5, Daniel Flick wrote:
> On Tuesday, October 17, 2017 at 5:01:13 PM UTC-5, Peter Otten wrote:
> > Daniel Flick wrote:
> > 
> > > On Tuesday, October 17, 2017 at 4:25:02 PM UTC-5, Daniel Flick wrote:
> > >> <SNIP>
> > >> Peter, I am not following.  Are you saying that there is a function that
> > >> returns the network only?  network_address was giving me the mask
> > >> attached to the end but maybe I was doing something wrong.
> > >> 
> > >> For an input of LAN_IP=192.168.99.1/24
> > >> ipaddress.IPv4Interface(LAN_IP).ip
> > >> returns 192.168.99.0/24
> > >> 
> > >> I need the 192.168.99.0 part only.
> > > 
> > > OOPS!  I meant
> > > For an input of LAN_IP=192.168.99.1/24
> > > ipaddress.IPv4Interface(LAN_IP).network
> > > returns 192.168.99.0/24
> > 
> > In the body of your post you had 192.168.1.128/25, so I mistook 
> > 192.168.1.129/25 as a typo. However, once you have
> > 
> > >>> import ipaddress
> > >>> ipaddress.ip_interface("192.168.99.1/24").network
> > IPv4Network('192.168.99.0/24')
> > 
> > you can simply add the step from my first answer:
> > 
> > >>> ipaddress.ip_interface("192.168.99.1/24").network.network_address
> > IPv4Address('192.168.99.0')
> > 
> > Unless I'm misunderstanding again...
> 
> That seems to be spot on.  I will try that.  I used the /25 to illustrate that that the network may not end in zero.  I had asked this question in the Mako forum and I had a few answers to drop the last octet and add zero which was not correct.  Thanks for your help!

SWEET!  That worked.  Thanks Peter!