"comprehend" into a single value

[Andrew Z]

and how about adding "IF" into the mix ?

as in :

a=0

dict= {10: ['a',1,'c'], 20: ['d',2,'f']}

for i in dict:

 p+= 10 if dict[i][1] in [1,2,3,4,5] else 0


can i "squish" "for" and "if" together ? or will it be too perl-ish ?





On Sun, Oct 8, 2017 at 12:37 AM, Andrew Z <formisc at gmail.com> wrote:

> Nathan, Bob - on the money. Thank you !
>
> On Sat, Oct 7, 2017 at 11:30 PM, bob gailer <bgailer at gmail.com> wrote:
>
>> On 10/7/2017 11:17 PM, Nathan Hilterbrand wrote:
>>
>>> dict= {10: ['a',1,'c'], 20: ['d',2,'f']}
>>> p = sum([dict[i][1] for i in dict])
>>>
>>> Something like that?
>>>
>> Ah, but that's 2 lines.
>>
>> sum(val[1] for val in  {10: ['a',1,'c'], 20: ['d',2,'f']}.values())
>>
>> On Sat, Oct 7, 2017 at 11:07 PM, Andrew Z <formisc at gmail.com> wrote:
>>>
>>> Hello,
>>>>   i wonder how  can i accomplish the following as a one liner:
>>>>
>>>> dict= {10: ['a',1,'c'], 20: ['d',2,'f']}
>>>> p = 0
>>>> for i in dict:
>>>>          p += dict[i][1]
>>>>
>>>>
>>>> Thank you
>>>> --
>>>> https://mail.python.org/mailman/listinfo/python-list
>>>>
>>>>
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>>
>
>