on a very slow function
Daniel Bastos
dbastos at toledo.com
Mon Oct 2 13:20:02 EDT 2017
ram at zedat.fu-berlin.de (Stefan Ram) writes:
> Daniel Bastos <dbastos at toledo.com> writes:
>> That function produces a function which yields the values of the
>> sequence x^2 - 1 mod N
>
> Thats a term with two free variables.
> I am not sure what the sequence is.
>
> And if that's
>
> ( x^2 - 1 )mod N
That's correct.
> there might be a way to calculate it without
> calculating the intermediate value of »x^2 - 1«.
I'd be amazed to see how.
Thanks!
More information about the Python-list
mailing list